Question

h'(t)=?
h(t)=2cot^2(πt +2)

Answer 1

have u tryed it yet?

Answer 2

Yeah... to be honest my brain isn't working right now

Answer 3

Take a break then :-D

Answer 4

You'll want to remember the chain rule here...


for:
\[u^n \]
then:
\[(n*u^{n-1})*\frac{d}{du}u\]
Do the power rule, then take the derivative of what's inside the "shell"/"layer"/"whatever"

Answer 5

@ agentx5 I know the chain rule, but like... okay..
\[h(t)=2\cot ^{2}(\pi t +2)\]
\[h'(t)=4\cot(\pi t +2)*\cot(\pi t +2)*-\sec^2(\pi t +2)(\pi)\]
... is there like double chain rule?
... I'ma go sleep after this

Answer 6

@agentx5 didn't tag properly

Answer 7

.. -sec^2 is supposed to be -csc^2.