Question

(2a+3a-1)-(1a-2a-1)

In the fist parenthesis 2a the A is squared and in the 2nd set of parenthesis 1a the A is squared.

Answer 1

Distribute a 1 to each term in the first set parentheses.
Distribute a -1 to each term in the second set of parentheses.

Answer 2

This will eliminate the parentheses all together and produce:
\[2a ^{2}+3a-1-1a ^{2}+2a+1\] from here you just combine like terms

Answer 3

okay what do you get. i get answer but the back of the book where i check my work gets a different answer.

Answer 4

what did you get? Type it out.

Answer 5

shouldn't the two be negative in the 2nd parenthesis from you distrubuting

Answer 6

No. It's already negative right? But then you distributed the -1 on the outside of the 2nd parentheses. A negative times a negative is always a positive.

Answer 7

Which is the same reason why the 1 at the very end is now positive.

Answer 8

i see what i did now. i think. I turned everything in the parenthesis into addition which in turn made them negative but when turning the whole problem into addition i forgot to turn the others back. does that make sense

Answer 9

Kinda. You end up getting the correct response?

Answer 10

i don't think so. :( hold on let me try it again

Answer 11

got it. thanks! Subtraction in Alegbra is so hard for me and i don't know why. i love algebra but can't do subtraction.