Question

Ok, I'm having trouble with a few integral problems, and finding the area.

y=x+1, y=9-x^2,x=-1, x=2

I keep getting 109/6 but my book says i should be getting 117/6

Answer 1

If someone gets another answer plz let me know how

Answer 2

yeah, i have got the answer : 117/6=39/2
try to make the picture first, then you will see the border of two curves, next process the integral to find the area

Answer 3

Ya that is exactly how I did it but I must be doing something wrong.

Answer 4

for the integral did you get (8x -(x^3)/3-(x^2)/2)?

Answer 5

no, for the integral i get (9-x^2 - (x+1) = (-x^2-x+8)

Answer 6

right you took the integral of that but after the integral was taken what did you get?

Answer 7

do you see what I'm saying?

Answer 8

for the integral (-x^2-x+8), [-1,2]
i think u can solve it

Answer 9

sorry, i cant say more,, my English too bad :(

Answer 10

I got -(x^3)/3-(x^2)/2+8x from the integral is that what you got

Answer 11

the first, subtitute for x=2, we will get ....
next, subtitute for x=-1, we will get ....
subtract both

Answer 12

ya, Ive done that like 20 times still getting 109/6..... even with a calculator

Answer 13

u should get the answer :
(-8/3 - 2 + 16) - (1/3 - 1/2 -8)

Answer 14

k, thank you!! I was forgetting the 3 on the bottom of my x^3 term, I knew it had to be something simple i was just missing it

Answer 15

yaw, sorry i cant explaind to u too more... i have a problem, with language here :'(