Question

How many atoms of phosphorus are in 9.20 mol of copper(II) phosphate?

Answer 1

@zepp :)

Answer 2

@Callisto

Answer 3

Using the magic number of Avogadro :)

Answer 4

\(\large6.02214*10^{23}\) atoms in a mole

Answer 5

so ? what else?

Answer 6

Nothing

Answer 7

huh? O_O

Answer 8

\(\large 9.20 \text{mol}*6.02214∗10^{23}\)

Answer 9

5.54x10^24 ?

Answer 10

Yep

Answer 11

Wait wait, I didn't read the question correctly....

Answer 12

There's something?!
No. of mole of copper(II) phosphate Cu3(PO4)2 = 9.20 mol
In one mole of Cu3(PO4)2, there are 2 mole of PO4 .....

Answer 13

can you explain more callisto?

Answer 14

Yeah, should be 18.4 mol

Answer 15

oh so you mean just double the 9.20 cuz there are 2 PO4

Answer 16

2PO4 => 2P => double

Answer 17

and do i have to take that number multiply by the Avogadro's number or something?

Answer 18

no. of atoms = no. of mole x Avogadro's number
You've only got the no. of mole of P.

Answer 19

yeah so take that 18.4x6.02214x10^23

Answer 20

to get no. of atoms

Answer 21

Yes, I think.

Answer 22

what do you mean? lol :|

Answer 23

i got 1.11x10^25 not sure if that's correct

Answer 24

I think that's the way of doing this question. But I'm not sure. After all, I haven't studied chemistry for more than 2 months :|

That should be correct...

Answer 25

ok it's correct cool :D thanks!

Answer 26

Welcome~