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Chemistry 9 Online
OpenStudy (anonymous):

a

OpenStudy (anonymous):

@zepp

OpenStudy (anonymous):

what's wrong zepp? why you keep disappearing and appear again?

OpenStudy (anonymous):

How many atoms are in 197 g of Calcium

OpenStudy (zepp):

Ask my internet, he shall give you the answer ;[

OpenStudy (zepp):

Internet cutting off from time to time, can't do anything for that lol

OpenStudy (zepp):

First you need to transform that 197g into mol, remember to always work with appropriate units.

OpenStudy (anonymous):

how do you transform that into mol?

OpenStudy (anonymous):

just put 197/1 ?

OpenStudy (zepp):

First you need to know Calcium's density, how many grams per mole, then the rest is a ratio problem

OpenStudy (zepp):

omg I feel like taking my router and kick it lol

OpenStudy (anonymous):

\[197 g Ca (\frac{1 mole Ca}{40.08 g Ca})(\frac{6.022x10^{23}}{1 mole Ca})=\]

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