State the number of turning points of the graph of a fifth-degree polynomial if it has five distinct real zeros??? a.3 b.5 c.4 d.6
Like number of inflections?
lol idk your asking the wrong person...sorry
i would say: 2nd degree doesnt turn at all 3rd degree turns once 4th degree turns twice 5th degree turns three times
not 100 percent about that though to be honest
well it works for me!...thanks for trying:)
i bet one of these guys knows better than i
I think it's 4. The maximum number of zeros is can have it 4 I believe which means that it needs to cross the x axis 3 times which means it needs 4 peaks.
maximim number of zeros is 5 I should say
Yea i guess it depends if they mean Max/mins or inflections
Poorly worded question in my eyes.
hahaha i agree!..well thanks for your help guys im gonna go with 4
yea go with 4..
here is a better way to think of it than what I said before. Its derivative is a fourth degree polynomial which means it has 4 critical points. A critical point could, but doesn't have to be a "turning point". But since the function crosses the x axis 5 times they must all be turning points, since it requires 4 changes of direction to do this. I am not guessing anymore i'm quite confident the answer is 4.
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