3. An object travelling at a speed of 40 m/s starts to accelerate uniformly with acceleration 5 m/s2. What would be the speed of the object 2 seconds later?
you can use one of the equations of uniform acceleration u = 40, t = 2 , a = 5, v = ? v = u + at v = 40 + 5*2
what does u means?
u = initial velocity the formula can also be written as v(t) = v(0) + at v (0) = velocity at time 0 and v(t) is vel. at time t
- thats the better way i think the 'u' formula is whats taught in the UK
to know the final velocity of an object after time 2 sec formula is final velocity(v)=initial velocity(u)+uniform accelration(a)*time of travelling(t) so v=u+a*t v=40+5*2 v=40+10 v=50
1. A train is travelling with a constant acceleration of 0 m/s2. At time t = 0 s, it is travelling at a speed of 15 m/s. What is the distance travelled by the train from time t = 0 s to t = 3 s?
for this ques how do I find the distance?
distance(s)=initial velocity(u)*time(t)+0.5 *accelaration(a) *t *t s=15 *3+0 .5 *0 *3 *3 s=15 *3 s=45
okay! thanks alot:)
yw
its ok yar
giv me a medal yar for my help jojoonggg
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