for what values of k is the locus of P(x,y) PF'-PF=k a hyperbola, pair of rays, null set.
k must be >0
for what
I'm still having a mental block with this:- If P is on the hyperbola and the F's are the foci then k is 2a (ie constant) by definition
what happens to the hyperbola when 2a=2c
You hace c^2 = a^2-b^2 For c to equal a then b must be 0
so the hyperbola becomes a line segment along x axis.. yeah?
No, it is just not a hyperbola
so do u get my queston now? :x
No, a hyperbola (centred on (0,0) is x^2/a^2-y^2/b^2 = 1 (b cannot be 0)
the locus doesnt have to be a hyperbola? for what values of k is the locus of P(x,y) PF'-PF=k a hyperbola, pair of rays, null set.
a>b>0 is part of the definition of a hyperbola
In your question, k=2a and is constant
I think you are trying to ask a different question.
but when k=2a=2c, hyperbola does not exist
a=c is not defined for hyperbola
k>c for locus to be hyperbola. what happens when k=c? should be a pair of rays
Why are you making up definitions for hyperbola, there are standard definitions to use.
Any other definition will not be a hyperbola
im not.. it was a question my test which asked that. it deosnt have to be a hyperbola
Well, that's a different question....... But you are using P(x,y) which is the usual notation for a point on a hyperbola and F, the usual notation for a focus.
ie you are assuming a hyperbgola to start with.
how about.. when k=2c for sum of distances, the locus is a line segment |dw:1342530518606:dw||dw:1342530602029:dw|
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