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Mathematics 14 Online
OpenStudy (anonymous):

A dice is rolled twice. Find the probability that the sum of the numbers on the dice is divisible by 3 or 4 a) 1/3 b) 2/4 c) 5/6 d) 5/9

OpenStudy (anonymous):

i.e. find the probability you roll a 3, 4, 6, 8, 9 or 12

OpenStudy (anonymous):

it can be B

OpenStudy (anonymous):

so u mean like the answer is half ?

OpenStudy (anonymous):

am getting 6 /12 @ satellite73

OpenStudy (anonymous):

the possiblity pairs that their sum is divisible by 3 or 4 are (1,2)(2,1)(2,2)(3,3)(4,2)(2,4)(4,4)(6,3)(3,6)(6,6) nof ways=10/18 5/9

OpenStudy (anonymous):

seems like it will be larger than 1/2 to me

OpenStudy (anonymous):

@sai1234 has it.

OpenStudy (anonymous):

2 ways to get a 3 3 ways to get a 4 5 ways to get a 6 5 ways to get an 8 4 ways to get a 9 1 way to get a 12

OpenStudy (anonymous):

5/9

OpenStudy (anonymous):

option d is correct. make table.

OpenStudy (anonymous):

36 total options of sums given two die rolls. Only 20 out of 36 are divisible by 3 or 4. A quick table would've helped explain this.

OpenStudy (anonymous):

i made a table and it got messy is it supposed to add up to 36?

OpenStudy (anonymous):

|dw:1342533019363:dw|

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