Question

Differentiation.

Answer 1

If the volume of a sphere increases at a constant rate Q, then the surface area of the sphere increases at the rate of (when the radius of the sphere is R)

Answer 2

are you sure there's no data missing here

Answer 3

ans is 2Q/R

Answer 4

use this
\[\huge \frac{dA}{dt}=\frac{dA}{dV} \frac{dV}{dt}=\frac{\frac{dA}{dr}}{\frac{dV}{dr}}\frac{dV}{dt}\]
A :surface area
V : Volume
r :radius of sphere