A triangle has side lengths 20, 21, and 40. Is the triangle acute, right or obtuse? Answer a. Acute b. Obtuse c. Right d. Not a triangle
Can someone explain how to do that?
it is a triangle because any 2 lines is longer than the other line 20 + 21 = 41 - just 1 longer than 40 - so it will be obtuse
ok thanks now i understand
looks something like |dw:1342545891034:dw|
yw
Hint: a^2 + b^2 > c^2 = acute a^2 + b^2 < c^2 = obtuse
You can't use @cwrw238's method because any two sides of a triangle is always longer than the third side no matter what
your equations are of course correct hero but this as an extreme case so my method did work in this scenario
How is this an extreme case? It's just a triangle like any other. It will either be acute or obtuse.
Your method is indeed flawed and not the logic that is used to solve these
hmmm
Okay for example, you have sides 6,7,8
could you help with me latest problem?
According to your method, since 6 + 7 = 13 and 13 > 8 , then that means the triangle is obtuse right? @cwrw238
But it is in fact acute
no - the 21 and 20 sides have a sum which is only 1 more than the 40 and they are only about half the length of 40 so it is obvious that the angle as drawn will be obtuse!! thats what i meant when i said it was an extreme case.
Either way, your method is inconsistent and should not be used to determine these. I'm pretty sure I can find a counter example to your claim
yours is the correct general method but in this case I just used plain common sense - its as simple as that
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