If your employer asked you to select one of these options: a) Your salary for the next two months will be $5,000, b) 1 penny for the first day and then he will double your salary every day for the entire month, which one should you pick? How much will you have at the end of 30 days?
A penny or a dollar?
a penny
wow i wish i could get this job!
i know right!!
penny...right
option b
i knew it was option B but I wasn't sure how much it would be. I detest logarithms!!
or even the formula
day one 1 cent day two 2 cents day three 4 cents day four 8 cents day five 16 cents haven't made much yet day six 32 cents day seven 64 cents double each time general idea is that at day \(n\) you will make \(2^{n-1}\) cents to try \(2^{30}\) on your calculator (assuming the month has 31 days) and be amazed at how much money you will have
\[a _{n}=a _{1}*r ^{n-1}\]
where a1 = 0.01, r = 2, and n = 30
looks like about \(1073741824\) pennies or \(\$10,737,418.24\)
in order to find the amount on the 30th day. not the sum.
@satellite73 gave the grand total.
true the total will be twice that much minus one cent
the amount you'd receive on day 30 alone is like $5M
oh my mistake i didn't read the 30 days in the month part sorry
thanks for your help...I wish ya'll were my tutors everyday...ughhh I have finals on Saturday
should be \(2^{39}\) for the 30th day for a total of \(2^{30}-1\)
damn typo \(2^{29}\) for the 30th day, \(2^{30}-1\) in total
No the power is subtracted by 1
It's cool.
what @coreylvaughn said i made a typo there
39th power would be sweet too though @satellite73 ! : )
so the final salary would be $10,737,418.24 times 2 -1?
Just $10,737,418.23
.23
I'll type the equation for geometric series...
okay i see that is the sum at the end of 30 days... Im slow with algebra please forgive me
\[S _{n}={a _{1}(1-r ^{n})\over(1-r)}\]
\[S _{30}={0.01(1-2^{30})\over(1-2)}\]
\[=$10,737,418.23\]
thanks :)
Anytime. Take care
I would pick the penny option. In 30 days (about one month) you would make about $536,870,912! Wish I were paid like that.
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