Rearranging this formula
In terms of E
My plan was to invert both equations. multiply the powers by 1/3 to cancel them out. Multiply across and take -1 from both sides.
I have the solution, but I cannot get it.
how much u getting ?
@ganeshie8 11,468
should be 8913
hmm your answer looks correct. wolfram gives the answer around yours : 11380 http://www.wolframalpha.com/input/?i=%281%2F%281%2B%28x%2F%281.092*3*1000%29%29%5E3%29+%3D+.0233
I got the solution there, it still doesn't make sense to me how the textbook got this result
gotcha !! http://www.wolframalpha.com/input/?i=%281%2F%28%281%2Bx%2F%281.092*3*1000%29%29%5E3%29+%3D+.0233
guess we both did the same mistake - assuming cube only to the second term of denominator lol
textbook simplified LHS as: 1/x^3 = (1/x)^3
@ganeshie8 I still don't get how wolfram is even doing that :[
I mean it just skips a lot of steps in between.
yeah. till which step u understand textbook ?
does second step makes sense ?
on wolfram?
nope. ur textbook : 2.jpg
No, I don't get the whole 3 square root thing
I can see that the textbook multiplies out the dominator and divides the square root
okay. lets see whats happening when we move from First step -> Second step
My problem is definitely understanding \[3\sqrt{0.0233}\]
or where it comes from
You just take cube root of both sides.......
thats right. just after first step, 1) by using reflexive property, write, LHS = RHS as , RHS = LHS
a=1/b^3 -> cubert(a) = 1/b
@ironictoaster, did you get estudier explanation ?
Nope : [ I'm looking for a example online about. It's stupid things like this that screws up exams for me.
its okay. im listing down steps. see if they make sense : just after first step, 1) by using reflexive property, write, "LHS = RHS" as "RHS = LHS" 2) take cube root both sides. then its Second Step
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