Question

Part 1: Explain, in complete sentences, which method you would use to solve the following system of equations. (1 point)

Part 2: Explain why you chose that method (1 point)

Part 3: Provide the solution to the system. (2 points)

x – 2y + z = 0
2x – 3y – 4z = –9
x + 2y – 5z = 0

1. I used elimination method
2. I used it cause it's easier than the rest.
3. I got ((97/8,10/3,23/18)

Can anyone double-check my solution?

Answer 1

@waterineyes

Answer 2

Sure why not..

Answer 3

Yeah I will also prefer elimination here..

Answer 4

Reason is:

The first and third equation consists same x and 2y so that they can be cancelled out by just addition or subtraction..

Answer 5

Let me solve this please wait.

Answer 6

K no problem :)

Answer 7

Add first and third equation you will get:

2x - 4z = 0

2x = 4z ---------------------1

Now multiply first equation with 3 and second equation by 2:

3x – 6y + 3z = 0
4x – 6y – 8z = –18

Now subtract them:

-x + 11z = 18

-2z + 11z = 18

9z = 18

z = 2

Answer 8

I got z = 2 check your solution once again @Loujoelou

Answer 9

K. I thought my solution was a bit weird.

Answer 10

K I see how you got z, and I realize x=4 correct?

Answer 11

@waterineyes Now I got (4,3,2)

Answer 12

x = 2z

if z = 2 then surely x will be 4..

Answer 13

Yes you are right now..

Answer 14

May I suggest you something?

Answer 15

Of course.

Answer 16

You can verify your answer..
See you got 4, 3 and 2,

Just plug in these values in the equation given and check whether they are coming equal..
Like for first:

x – 2y + z = 0

4 - 2(3) + 2 = 0

6 - 6 = 0

0 = 0

This means your answer is correct..

Now similarly put in second and third you will get 0 in each case..

This is how we verify our answers..

Answer 17

K :D Tyvm @waterineyes

Answer 18

Welcome Dear.. \(\huge \checkmark\)