geometry help. http://is.byu.edu/courses/hs/GEOM-043-101/secure/imgs/math10-2305.gif
Calculate the surface area of a regular triangular pyramid with the base edges of length 12 and a slant height of 12. (Hint: Remember that the base of a regular triangular pyramid must be an equilateral triangle, not necessarily congruent to the sides of the pyramid.)
Hint: Count the surfaces and find the area of each sides.
http://hotmath.com/hotmath_help/topics/surface-area-of-a-pyramid.html lateral surface area (the 3 sides) is = p*s/2 where p is the perimeter of the base and s is the slant height.
yea thats wat i got but i wasnt sure
can u guys help me in one more question
plz
the area of the bottom is the area of an equilateral triangle sqrt(3)*a^2/4 where a is the length of 1 side
Approximate the volume of the regular triangular pyramid in problem 12 if the height is approximately 11.5. (Hint: Remember that the base of a regular triangular pyramid must be an equilateral triangle, not necessarily congruent to the sides of the pyramid.)
thats another question ^^
I did not get 288. I got 278.35 rounded to 278
y did u get 278. i got 288
the base is an equilateral triangle with sides = 12 so its area is sqrt(3)*12*12/4 see http://en.wikipedia.org/wiki/Equilateral_triangle
the top is 3 * 12*12/2 = 216
SO THE answer is 216?
i did it like this look
the surface area includes the top (3 sides) plus the bottom
SA= A+3/2(SL) = 72+ (3/2(144) 72+3(72) 72+216= 288
how did you get A= 72?
BASE AREA= 1/2(A)(S) = 1/2 (12)(12) 1/2(144) =72
Your questions tells you (Hint: Remember that the base of a regular triangular pyramid must be an equilateral triangle, not necessarily congruent to the sides of the pyramid.) that is saying the bottom triangle is an equilateral triangle with 3 sides = 12 the 3 sides on top are not equilateral triangles.
so use the formula for the area of an equilateral triangle for the base A
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