Question

3p^2+12p-2=0 how do you solve this problem? I need all the steps please and thank you.

Answer 1

You have to use the Quadradic Formula here, it's not solvable by factoring:
\[x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\]

Answer 2

To be clear that's for the standard form:

ax^2 + bx + c = 0
a = 3
b = 12
c = -2

See how that works?

Yes, you will get two answers, as you should (because of the x\(^2\))

Answer 3

okay

Answer 4

If what is under the radical/square-root above is negative you'd have two imaginary roots, thankfully you won't here. But you will have square-roots (or fractional powers if you prefer) in your final answers.

Answer 5

okay

Answer 6

is it \[x=12\pm \sqrt{120} \over 6\]