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Mathematics 15 Online
OpenStudy (anonymous):

We toss two dice 1,000 times. How many times do we expect to have the sum of the two dice equal to 4? can someone explain how i do this ?

OpenStudy (anonymous):

(1,3) (2,2) are set the to get a sum of four. Can you find the probability of getting this?

OpenStudy (anonymous):

i know how you came up with those numbers but not sure what i have to do with them to get the answer

OpenStudy (anonymous):

How many possibilities are there ?

OpenStudy (anonymous):

like this?

OpenStudy (anonymous):

its a 1 in 6 chance to get the numbers ?

OpenStudy (anonymous):

or each number

OpenStudy (anonymous):

is thre a formula i use for this specific kind of question ?

OpenStudy (anonymous):

Nope. Create the sets. (1,1), (1,2).......(6,6) There would be 36 outcomes rt?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

theres 3 sets of numbers that add up to 4 out of the 36 possibilitys

OpenStudy (anonymous):

Three? or two?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

(1,3) (2,2) (3,1)

OpenStudy (anonymous):

(1,3) and (3,1) are same you can't differentiate actually.

OpenStudy (anonymous):

ok wasnt sure

OpenStudy (anonymous):

So 2/36 is your probablty. Now multiply with 1000 to get the no.

OpenStudy (anonymous):

i ended up with 55.55555 the multiple choice answers were A-about 250 B-about167 C-about 83 D-about 42

OpenStudy (anonymous):

i do something wrong or am i just supposed to decide which number im closest to ?

OpenStudy (anonymous):

i divided 2/36 and multiplied it by 1000 to get that number

OpenStudy (anonymous):

I guess 55 is correct. They might have considered (1,3) and (3,1) as separate. Then you'd get 83.

OpenStudy (anonymous):

and thats one of the options so i guess thats my answer ?

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