Question

Can someone please explain how to do this?
what are the zeros of the polynomial function y=x(x-6)(x+3)(x-11)?

Answer 1

when you have several numbers multiplied together and get zero, then this implies at least one of those numbers MUST be zero - greed?

Answer 2

*agreed

Answer 3

agreed

Answer 4

the first is x = 0

then you need to solve
x - 6 = 0
x + 3 = 0
x - 11 = 0

to find the 4 zeros

Answer 5

good, so if you say,

a(b-1) = 0

then you know that either a=0 OR b-1 = 0

Answer 6

because here you are multiplying two numbers together - 'a' and '(b-1)'

Answer 7

ok that makes sense!

Answer 8

gr8! so, in your case you need to consider each number being zero

Answer 9

where the numbers to consider are:

x
(x-6)
(x+3)
(x-11)

Answer 10

x(x-6)(x+3)(x-11)=(x)(x-6)(x+3)(x-11)

set each parenthetical group to 0
x=0
x-6=0
...

and then solve so the solutions are 0,5,-3,10

Answer 11

great thanks so much for all the help!!...what my teacher tried to teach in an hour i just learned in 5 min haha

Answer 12

yw :)