Mathematics
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OpenStudy (anonymous):
If the sum of p, q, r, and s is 16, what is the avergae of p+2s, r-q, 2q+5, and 7-s?
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OpenStudy (anonymous):
average*
OpenStudy (klimenkov):
Average of 4 values \(a,b,c,d\) is \(\frac{a+b+c+d}4\). Try to use this.
OpenStudy (anonymous):
but how do i relate that to the average of the four terms in the last part
OpenStudy (klimenkov):
Write the average of your values right here.
OpenStudy (anonymous):
4
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OpenStudy (klimenkov):
Average of what values did you write?
OpenStudy (anonymous):
(p+2s)+(r-q)+(2q+5)+(7-s)/4
OpenStudy (klimenkov):
So why did you get 4?
OpenStudy (anonymous):
i thought u asked for the average of p q r and s
OpenStudy (klimenkov):
What is the problem for you now?
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OpenStudy (anonymous):
how to find the average of that using 16
OpenStudy (anonymous):
because q+ r+ p+ and s = 16
OpenStudy (klimenkov):
Try to simplify this ((p+2s)+(r-q)+(2q+5)+(7-s))/4.
OpenStudy (anonymous):
\[p+2s+r-q+2q+5+ 7-s=12+p+q+r+s=12+16=28 \]\[\frac{28}{4}=7 \]
OpenStudy (anonymous):
p+s+r+q+7/4
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OpenStudy (klimenkov):
Do you see the last step to get the answer?
OpenStudy (anonymous):
add 16 and 7 and divide by 4?
OpenStudy (anonymous):
i mean 16 and 12
OpenStudy (anonymous):
so 28/4=7
OpenStudy (klimenkov):
I think you have made a mistake.
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OpenStudy (anonymous):
thx i got it!
OpenStudy (klimenkov):
Yes. You are right!
OpenStudy (anonymous):
:D
OpenStudy (klimenkov):
Ask me anything you like. You are welcome.