Mathematics
7 Online
OpenStudy (anikate):
simplify: a+b+3a^2 -3b^2
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OpenStudy (asnaseer):
think back to your previous question, remember I showed you that:\[a^2-b^2=(a+b)(a-b)\]
OpenStudy (anikate):
yeah but Hw do I use it to this?
OpenStudy (asnaseer):
look at the last two terms in your equation - factor out the 3 and what will you get?
OpenStudy (anikate):
3(a^2 -b^2)
OpenStudy (asnaseer):
now can you spot anything?
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OpenStudy (asnaseer):
ok @Anikate back to your question
OpenStudy (anikate):
ok
:)
OpenStudy (asnaseer):
so you factored out a 3 from the last two terms to get: \(3(a^2-b^2)\)
Can you now spot how to factorise this?
OpenStudy (anikate):
ummm...
OpenStudy (asnaseer):
look at my first reply to this question above ^^^
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OpenStudy (anikate):
a+b+3(a+b)(a-b)
I think?
OpenStudy (asnaseer):
perfect!
now you see you have (a+b) at the start of this expression, and also (a+b) in the term 3(a+b)(a-b)
OpenStudy (asnaseer):
so you should be able to factor out the (a+b)
OpenStudy (anikate):
which one?
OpenStudy (asnaseer):
both
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OpenStudy (anikate):
could u plz show me how? I am not so bright...
OpenStudy (asnaseer):
imagine you had: x + 3xy
you could factor out the x to get: x(1+3y)
OpenStudy (asnaseer):
now just think of the 'x' as being 'a+b'
OpenStudy (anikate):
huh?
OpenStudy (asnaseer):
you have: a+b + 3(a+b)(a-b)
which we can write as: (a+b) + 3(a+b)(a-b)
think of the (a+b) term as being a single number, say 'x', and factor it out
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OpenStudy (asnaseer):
how would you factor out the 'x' in: x + 3x(a-b)
OpenStudy (anikate):
um where did u go?
OpenStudy (asnaseer):
I was waiting for you to reply.
OpenStudy (anikate):
I was confused a bit?
OpenStudy (anikate):
3(2a+2b)(a-b)?
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OpenStudy (anikate):
sry 2 keep u waiting
OpenStudy (asnaseer):
remember I cannot see you - so on sites like this it is important to give feedback via chat otherwise it is very difficult to help.
OpenStudy (anikate):
sry
OpenStudy (asnaseer):
so, my last question to you was:
how would you factor out the 'x' in: x + 3x(a-b)
OpenStudy (anikate):
3(2a+2b)(a-b)
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OpenStudy (asnaseer):
plz read my question carefully - your answer should contain an 'x' in it:
how would you factor out the 'x' in: x + 3x(a-b)
OpenStudy (anikate):
4x(a-b)
OpenStudy (asnaseer):
ok - I see where you are confused now
OpenStudy (anikate):
ok
OpenStudy (asnaseer):
what you did was the correct factorisation of: x(a-b) + 3x(a-b)
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OpenStudy (asnaseer):
what we have is: x + 3x(a-b)
think of this as 'x' times one, plus 'x' times 3(a-b)
OpenStudy (anikate):
k right now on the paper I am at a+b+3(a+b)(a-b)
OpenStudy (anikate):
4x(a-b)
OpenStudy (asnaseer):
that is also wrong
OpenStudy (asnaseer):
\[a+b+3(a+b)(a-b) = (a+b)\times1+(a+b)\times3(a-b)\]
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OpenStudy (asnaseer):
if we now pull out the (a+b) terms, we end up with:\[(a+b)(1+3(a-b))\]
OpenStudy (asnaseer):
does that make sense to you?
OpenStudy (anikate):
umm.. no
OpenStudy (asnaseer):
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