Question

balance:
Li + CO2 + H2O = LiHCO3 + H2

Answer 1

@zepp

Answer 2

busy man

Answer 3

when you balance the CO2 do you count it as CO2 or C and O are separated ?

Answer 4

lemme see

Answer 5

2 Li + 2 CO2 + 2 H2O = 2 LiHCO3 + H2

Answer 6

2,2,2,2 any explanation? :P

Answer 7

why taking so long ?

Answer 8

dont make it too complicated zepp o_o

Answer 9

Alright
\[\large \text{Li} + \text{CO}_2 + \text{H}_2\text{O} = \text{LiHCO}_3 + \text{H}_2\]At the first glance, we need more H on the left side, just 1 more, we need 3.

So\[\large \text{Li} + \text{CO}_2 + \color{red}{2}\text{H}_2\text{O} = \text{LiHCO}_3 + \text{H}_2\]Now we have 4 H on left side, 3 H on right\[\large \text{Li} + \text{CO}_2 + \color{red}{2}\text{H}_2\text{O} = \color{red}{2}\text{LiHCO}_3 + \text{H}_2\]Now equal amount of H, although we have 4 O on left, 6 O on right, pick on that's not with H so we won't affect the H balance\[\large \text{Li} + \color{red}{2}\text{CO}_2 + \color{red}{2}\text{H}_2\text{O} = \color{red}{2}\text{LiHCO}_3 + \text{H}_2\]Now we have 6 O on both left and right, but 1 Lithium on left and 2 Lithium on right\[\large \color{red}{2}\text{Li} + \color{red}{2}\text{CO}_2 + \color{red}{2}\text{H}_2\text{O} = \color{red}{2}\text{LiHCO}_3 + \text{H}_2\]And voila!

Answer 10

gosh...told u to not make it complicated haha :))

Answer 11

It's all about derping on one side and another :P

Answer 12

i kinda...get it, let me try the next equation

Answer 13

CaH2+H2O = Ca(OH)2 +H2

Answer 14

Only thing that makes it difficult it the 2 hydroxyde.

Answer 15

ok just to making sure, are the H balanced on both side already ?

Answer 16

Yes, but you'll have to tweak with it though

Answer 17

ok here's what i got: 1,2,1,2

Answer 18

That's right :)

Answer 19

cool :)

Answer 20

Next question:
Write and balance the equation for the decomposition of aluminum chloride into its elements. Phase symbols are optional.

Answer 21

Decomposition involves \(\large \text{O}_2\).

Answer 22

Aluminum Chloride = \(\large \text{AlCl}_3\)

Answer 23

so decomposition always involve O2 ?

Answer 24

Actually, it doesn't xD

Answer 25

I was thinking of rusting process

Answer 26

i know decompositon is like C --> A+B, in this case AlCl3 is the "C" so what's A and B ?

Answer 27

Al and Cl ? o_0

Answer 28

\[\large \text{AlCl}_3\rightarrow \text{Al}+3\text{Cl}\]

Answer 29

Nope, should be \(\large AB \rightarrow A+B\)

Answer 30

ohh

Answer 31

why the 3 is in front of CL ?

Answer 32

because of the formula of decomposition: \(\large AB \rightarrow A+B\)

Answer 33

So \(\large \text{AlCl}_3 \rightarrow \text{Al}+\text{Cl}\)
and you simply balance it.

Answer 34

Ohh zepp u didnt told me you already balanced it wth o_0

Answer 35

confused a bit by the 3 ahah

Answer 36

thanks @Blitzkrieg :D

Answer 37

Well that was the rough equation, you still need to balance it
\[\large \text{AlCl}_3 \rightarrow \text{Al}+\text{Cl}\\\large\text{AlCl}_3 \rightarrow \text{Al}+\color{red}{3}\text{Cl}\]

Answer 38

hmm but it seems wrong when I put it in, it said "Recall that elemental chlorine is diatomic" ? what's wrong here?

Answer 39

yeah i did included the 3 also

Answer 40

Diatomic... Cl2

Try \(\large 2 \text{AlCl}_3 = 2 \text{Al} + 3 \text{Cl}2\)

Answer 41

why is there a 2 on the back of Cl ?

Answer 42

oh nvm i got it

Answer 43

Diatomic

Answer 44

\[\large 2 \text{AlCl}_3 = 2 \text{Al} + 3 \text{Cl}_2\]

Answer 45

ok i got it :D

Answer 46

next question please:
Write the equation for the combination of nitrogen and hydrogen to form ammonia, NH3. Phase symbols are optional.

Answer 47

So you need to write a chemical equation for
Nitrogen(N) + Hydrogen (H) to form Ammonia

Answer 48

and again, N and H are diatomic elements

\[\large \text{N}_2+\text{H}_2=\text{NH}_3\] then you simply balance it

Answer 49

what is the charge on ammonia?

Answer 50

We have no use of charge here.

Answer 51

i just want to know :P

Answer 52

We've already set up an equation, all you have to do it to balance it

Answer 53

It's neutral