Question

integrate cos(pi/x)/x^2 from [2,infinity]

Answer 1

the answer is 1/pi im just not sure on the process

Answer 2

\[\cos(\pi/x)/x^2\] Use u substitution with u being pi/x so that du = \[-\pi/x^2 dx\].

Answer 3

ok thanks!

Answer 4

ok so i substituted in u and du but my solution was 1
where -(sin(pi/infinity)-sin(pi/2)

Answer 5

*is equal to one

Answer 6

you forgot about pi

\[du = -\pi/x^{2} dx\]
so
\[dx = -x^{2}/\pi du\]
\[\rightarrow -1/\pi \int\limits_{2}^{\infty}\cos(u) du\]
after integrating, you get 1/pi

Answer 7

thanks so much!