Can someone please help me with this problem? Its urgent!

Question

anonymous · Answer

$$x^2-x-6 \over x^2 - 4$$

anonymous · Answer

As I understand, if x is equal to 2, then x will be undefined, since the denominator will be 0! if its greater than 2, x can only be between 0.5 and 1! check it if you want to! Formally, the answer can be written as $$0.5 < x < 1$$

anonymous · Answer

when x is greater than 2!

anonymous · Answer

because for me it says the answer is $$x-3 \over x-2$$ and i am trying yo figure out how to go from point a to point b.

anonymous · Answer

@cfraser007 that didn't help much i am afraid.

ganeshie8 · Answer

$\frac{x^2-x-6}{x^2-4}$

$\frac{x^2-3x+2x-6}{x^2-2^2}$

$\frac{x(x-3)+2(x-3)}{(x+2)(x-2)}$

$\frac{(x-3)(x+2)}{(x+2)(x-2)}$

$\frac{(x-3)\cancel{(x+2)}}{\cancel{(x+2)}(x-2)}$

$\frac{(x-3)}{(x-2)}$

anonymous · Answer

@ganeshie8 where did you get −3x+2x from?

anonymous · Answer

...Wait a second. Isn't that a trinomial?

richyw · Answer

$-x=-3x+2x$ you just put that in so you can see how to factor it

anonymous · Answer

we use ac factoring in factoring the top.

anonymous · Answer

note that, its in the form ax^2+bx+c.

anonymous · Answer

identifying, a=1, and c=-6. so, ac = (1)(-6)

anonymous · Answer

then, try to find two numbers that when we multiply we get -6, but when we add, we get -1 (coefficient of the middle term).

anonymous · Answer

note that, (-3)+2 = -1, right? then use that to rewrite the middle term, its what richyw, did. :))

ganeshie8 · Answer

thats very good explanation of factoring :))

anonymous · Answer

thanks:))

ganeshie8 · Answer

thank you too ^_^