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x(x-2)y'+2y+=0 by using linear differential equation
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divide by x(x-2)
\[y'+\frac{2}{x^2-2x}y=0\]
find the integration factor \[\mu(t)\]
what's the p(x) and Q(x)?
there is no q(x) since this is an order 1 linear
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\[p(x)=\frac{2}{x^2-2x}\]
should i use partial fraction ?
yes
don't multiply it like i did
ok ,
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so the answer must be y(x-2)=cx?
what did you get from the integration factor
|dw:1342579395071:dw|
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