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OpenStudy (zepp):
?
OpenStudy (zepp):
That' wrong lol
OpenStudy (anonymous):
welcome back blitz! lol
OpenStudy (anonymous):
The number of Avogadro is used to find the number of atom in a mole
\[\text{Number of atoms in a mole}=\text{Number of mole} * 6.23*10^{23}\]
(I round the number)
OpenStudy (anonymous):
6.23 ? i thought its 6.02 ?
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OpenStudy (anonymous):
Sorry, I left a 0 behind :s\[1.65 × 10^{24}=\text{Number of mole} * 6.023*10^{23}\]
That should be our formula
OpenStudy (anonymous):
And the number of mole would be
\[1.65*10^{24}\div6.023*10^{23}\]
OpenStudy (anonymous):
that's what i did =.=
OpenStudy (anonymous):
(Division, not multiplication)
OpenStudy (anonymous):
yes! i did division wth :| what did u get?
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How many moles of Fe2O3 are in 235 g of the compound?
OpenStudy (anonymous):
ok let me try this first
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OpenStudy (anonymous):
Cool :)
OpenStudy (anonymous):
idk if i did it right or not, but my final answer is 1.47
OpenStudy (anonymous):
Alright so in Fe2O3, there's two Fe and 3 O
2(Fe)= 55.845*2 = 111.69
3(O)= 16*3 = 48
Fe2O3 = 111.69 + 48 = 159.69
Take the 235 and divide
235/159.69 = 2.1
OpenStudy (anonymous):
1.47, sorry, not 2.1
OpenStudy (anonymous):
So yep, that's right :)
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OpenStudy (anonymous):
:) thanks for the explanation !
OpenStudy (zepp):
yw :)
OpenStudy (anonymous):
not you, i was thanking Blitz ! lol
OpenStudy (zepp):
psh
OpenStudy (anonymous):
You are welcome :D
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OpenStudy (anonymous):
Blitz is a really helpful guy, he knows everything well, explain clearly, give good examples..everything you can ask of a tutors :0
OpenStudy (anonymous):
blitz is awesome :)
OpenStudy (zepp):
So I don't explain well? :(
OpenStudy (anonymous):
zepp you just lazyyy !! 50% of blitz muahahha :))
OpenStudy (zepp):
meh
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OpenStudy (anonymous):
@zepp I thought you need to be helpful here and not just talking rubbish... :/
OpenStudy (anonymous):
yup ! he need to be more helpful and not disconnecting too much! and also get a new ISP lol
OpenStudy (anonymous):
Next question? :D
OpenStudy (anonymous):
lol :) your so hyper
OpenStudy (anonymous):
How many moles of N are in 0.235 g of N2O?
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OpenStudy (anonymous):
i got this, just need you to chek my answer ok?
OpenStudy (zepp):
42 is the answer.
OpenStudy (anonymous):
wow...i said hold on lmao ! -.-
OpenStudy (anonymous):
wtf zepp ! screww u lol :D
OpenStudy (zepp):
:D
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OpenStudy (anonymous):
i got .0083 though ?
OpenStudy (anonymous):
It's NO2 or N2O?
OpenStudy (anonymous):
N2O !
OpenStudy (anonymous):
Alright, first step would be see how many g does 1 mole of this weight
2(N) = 14
1(O) = 16
N2O = 14+16 = 30
30g/mol of N2O
We have 0.235 g
We'll simply divide, how many 30g/mol fits in there?
\(0.235g\div30g/mol=0.007833mol\)
You forgot a 7 somewhere
OpenStudy (anonymous):
wait does the O even necessarily in this?
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OpenStudy (anonymous):
it only ask for "N"
OpenStudy (zepp):
omg I misread the question, hold on
OpenStudy (anonymous):
.....
OpenStudy (zepp):
What @Blitzkrieg did was correct, there's 2 moles of N in 30g.
OpenStudy (zepp):
Since there's 0.007833mol of N2O that fits in 0.235 and there's 2 moles of N in 1 mole of N2O, you multiply that number by 2
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