Question

y' = x-2y cot 2x ,,,, using linear differential equation..? help?

Answer 1

\[y' = x-2y \cot 2x\]\[y' +2y \cot 2x= x\]\[\mu(x)=e^{\int \cot 2x\text dx}\]

Answer 2

go on..

Answer 3

so whats the right answer?

Answer 4

hane you found the integrating factor \(\mu(x)\) ?

Answer 5

no,,have you found it ?

Answer 6

yes

Answer 7

shoe it please..

Answer 8

show it please

Answer 9

\[\mu(x)=e^{\int \cot 2x\text dx}=\dots\]

Answer 10

then what is the correct anwer?

Answer 11

what step are you having difficulty on

Answer 12

in finding the General Formula
..

Answer 13

\[\int \cot 2x \text dx=\frac 12\int \cot u\text du=\cdots\]

Answer 14

that's not a step,

Answer 15

so whats the general formula ?

Answer 16

please give me the right answer? its kinda hard to solve for me

Answer 17

im not going to solve the entire problem for you,
but i can help you with specific steps ,

if you'd rather help from a robot, try this http://www.wolframalpha.com/input/?i=y%27+%3D+x-2y+cot+2x

Answer 18

ok thanks for helping