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OpenStudy (anonymous):
n
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OpenStudy (anonymous):
16.5 g of carbon is _____ moles of carbon and ______ atoms of carbon.
OpenStudy (anonymous):
@zepp
OpenStudy (anonymous):
n = given mass/ molar mass
OpenStudy (anonymous):
n = 16.5/12 = 1.375 moles
OpenStudy (anonymous):
what about atoms ? i forgot how to get that
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OpenStudy (zepp):
Avogadro
OpenStudy (anonymous):
no of atoms of c = 6.02 * 10^ 23 * moles
OpenStudy (anonymous):
6.02x10^23 x 1.375 right?
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