A graduated cylinder contains 32.0 cm3
of Hg. If the density of Hg (@ 25˚C) is 13.534 g/cm3, how many moles of Hg are in the container?

Question

A graduated cylinder contains 32.0 cm3
of Hg.  If the density of Hg (@ 25˚C) is 13.534 g/cm3, how many moles of Hg are in the container?

anonymous · Answer

@zepp

zepp · Answer

How many g of Hg there are in the cylinder?

anonymous · Answer

13.534g

zepp · Answer

That's the density, what about in the cylinder?

anonymous · Answer

PV = NRT

anonymous · Answer

use this

lgbasallote · Answer

i think it's more of that molar mass thingy..since there's density

zepp · Answer

Define P,V,N,R and T, @Yahoo! ?

lgbasallote · Answer

what was that formula again?

anonymous · Answer

oh..no pressure is not given  hm!!!

zepp · Answer

$$\large \frac{13.534g}{1cm^3}=\frac{?g}{32cm^3}$$

zepp · Answer

There's 433.088 g of mercury in the cylinder.

lgbasallote · Answer

n = m/M

i believe that's the formula yes?
n is moles
m is mass
M is molar mass

lgbasallote · Answer

$$\text{mole} = \frac{\rho V}{M}$$

lgbasallote · Answer

or am i wrong?

zepp · Answer

From the periodic table, we know that 1 mole of Hg = 200.59 grams$$\large \frac{1mol}{200.59g}=\frac{?mol}{433.08g}$$

zepp · Answer

@lgbasallote That's the right formula.

lgbasallote · Answer

cool

lgbasallote · Answer

so it's a direct sub what's with this thingy then?

zepp · Answer

That's just a formula, I'm using the long method.

zepp · Answer

With ratio it's much easier to understand.

zepp · Answer

and they are quite the same thing so..

anonymous · Answer

so 2.15 amu?

anonymous · Answer

ok, im lost, so first you gotta convert from cm3 to g right?

zepp · Answer

mole*