The perimeter of a triangle is 40 inches. The second side exceeds twice the first side by 1 inch, and the third side is 2 inches less than the second side. Find the length of each side of the triangle
please help anyone?! :)
I can help if you promise me some chocolate.
Let the first side's length be x; and let's proceed sentence by sentence.
The second side exceeds twice the first side by 1 inch. How would you write this algebraically?
umm...
2+x+1?
im not suree =/
Twice implies multiplying, you are on the right track =D
Keep trying, you'll get it ;)
2x+x+1? im still not sure :(
Let the first side be x.then second side=x+1 third side=(x+1)-2 A/q, (x)+(x+1)+((x+1)-2)=40 x+x+1+x-1=40 3x=40 x=40/3
The second side exceeds twice the first side by 1 inch. Twice the first side means -> 2x Exceeds by 1 inch implies that's 1 inch more -> 2x+1 Got it?
ohhhh i get it
Alright so now we have First side = x Second side = 2x+1; Now, the third side is 2 inches less than the second side. How would you write that algebraically?
2x+1-2?
Excellent! We can simplify that: \(2x-1\)
oh ok
Alright, now we got First side = x Second side = 2x+1 Third side = 2x - 1 What's the definition of a perimeter?
40
I mean, the definition of 'perimeter'
when you add up all the sides?
That's right, so in our case; Perimeter = 1st side + 2nd side + 3rd side Now you know what to do! :)
Perimeter means the sum of all the sides . & this case is done with every geometrical shape
okk i'll remember that
So? What's your equation? :D
well i got stumped on it..
no nevermind!
Got it? :D
i made a slight error thats what messed me up
is it 10?
x = 10?
wait no
ahh 8
Let's see, definition of 'perimeter': sum of all sides of a geometrical shape. In our question, it would be the sum of all 3 sides First side = x Second side = 2x+1 Third side = 2x - 1 (x)+(2x+1)+(2x-1) would be our perimeter, which is 40 (x)+(2x+1)+(2x-1) = 40 x + 2x + 2x + 1 + 1 = 40 5x + 2 = 40 5x = 40 - 2 5x = 38 x = 38 \(\div\)5 x = 7.6
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