Question

If \[\LARGE{\color{green}{z+\sqrt{2}\space \space |z+1|+i=0.}}\]Then z = ?????

Answer 1

Where "z" is a complex number.

Answer 2

sqrt{2}|z+1| = -z - i

|z+1| is purely real. implying -z-i must be real as well. you can solve the rest now.

Answer 3

didn't gt :(

Answer 4

take z = x + iy and solve.

Answer 5

yeah i did that

Answer 6

but didn't gt answer

Answer 7

i gt 2 equations at last: -
\[y+1=0\]&\[x+\sqrt{2[(x+1)^2+(y)^2]}\]

Answer 8

but didn't gt answer:(

Answer 9

second equation =0*

Answer 10

\(x+iy+\sqrt{2}\cdot\sqrt{(x+1)^2+y^2}+i=0\)
That means you have a system of 2 equations:
\(x+\sqrt{2}\cdot\sqrt{(x+1)^2+y^2}=0\)
\(y+1=0\)
Solve it!

Answer 11

i have gt the same equation above
but didn't gt answer at last:/

Answer 12

u plz tell me
wt answer u get?

Answer 13

for x & y?

Answer 14

\(z=-2-i\)

Answer 15

oh yeah it is the answer but
i m nt getting
i put y = -1 in first equation.
but i m nt getting x =-2

Answer 16

Please, write your detailed solution. By steps.

Answer 17

ok!
oops sorry
i gt answer while writing steps
actually big mistake of plus / minus by me
sorry!
thanx for the help:)