Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

A question about the Bell Curve

OpenStudy (anonymous):

\[e ^{-0.5(x-\mu)^2/\sigma^2}/\sigma \sqrt{2 \pi}\] \[e ^{0.5(-(x-\mu)^2/\sigma^2)}/\sigma \sqrt{2 \pi}\] \[e ^{i(x-\mu)/\sigma}/\sigma \sqrt{2 \pi}\] \[(cos(x-\mu/\sigma)+isin(x-\mu/\sigma))/\sigma \sqrt{2 \pi}\]

OpenStudy (anonymous):

The last equation graphs nothing like the first, and I can't see why, as they should be the same thing.

OpenStudy (anonymous):

how did u get the third equation from the second one ? why there is iota there ?

OpenStudy (anonymous):

^0.5 is the square root

OpenStudy (anonymous):

\[\sqrt{-1}\sqrt{(x-\mu)^2}/\sqrt{\sigma^2}\]

OpenStudy (anonymous):

WHat's the question here?

OpenStudy (anonymous):

The first equation is the bell curve, but the second seems periodic, it will yield a completely different graph. How is this?

OpenStudy (anonymous):

I guess you are confused by the 0.5 in your starting formula. If you write it in the form: \[1/(\sigma \sqrt{2\pi} ) \times e ^{-[(x-\mu)/(\sigma \sqrt{2} )]^2} \] and use \[i ^{2} = -1 \] like you suggested, you get: \[1/(\sigma \sqrt{2\pi} ) \times e ^{[i^{2}(x-\mu)/(\sigma \sqrt{2} )]^2} \] This is just another way of writing the bell formula. I fact it is a non-periodic real function.

OpenStudy (phi):

You start with \[ e ^{0.5(-(x-\mu)^2/\sigma^2)}/\sigma \sqrt{2 \pi} \] and then re-write the 0.5 in the exponent as a square root. But notice that the square root is around \( e^{stuff} \) and not around \(stuff\) that is, the next step is \[ \sqrt{e ^{(-(x-\mu)^2/\sigma^2)}}/\sigma \sqrt{2 \pi} \] which is different than what you posted.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!