if (3-4i)(x+iy) = 1+ i.0 find x , y belongs to R , i = √-1

Question

anonymous · Answer

solve (3-4i)(x+iy)...you vl get wo terms...wih and without iota...equate the term without iota with 1 and with iota with 0...

anonymous · Answer

thank yu .. can you help me even better .. because when my teacher taught me i wer absent .. so i dont realy kno how to do this .. what is ( i ) ?

anonymous · Answer

i is iota...with the value of root -1...in dis question...iota trerm has to be equated to the rhs iota term and real term is equated with rhs real term...ask any odr question u vnt to ask..

anonymous · Answer

okay .. thanks .. :) so now i have to solve (3-4i)(x+iy) right ?

anonymous · Answer

yes...

unklerhaukus · Answer

$$(3-4i)(x+iy) = 1+0i$$$$3x+3yi-4ix-4yi^2=1+0i$$$$3x+(3y-4x)i+4y=1+0i$$$$(3x+4y)+(3y-4x)i=1+0i$$
$$3x+4y=1;\qquad3y-4x=0$$

anonymous · Answer

thank you @UnkleRhaukus  and @harsimran  :)

anonymous · Answer

anytym :)