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Find x and y if (x-yi)(2+3i) = x+2i/1-i.
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simple the Left hand side and rationalize the Right hand side of equation ; then compare real and imaginery parts of complex numbers from both side
well if you dont mind can yu do after this step .. (2x + 3y) + ( 3x - 2y )i = x + 2i / 1 - i. ?
well for rationalizing the right hand side u have \[\frac{x+2i}{1-i}=\frac{x+2i}{1-i}\frac{1+i}{1+i}=\frac{(x+2i)(1+i)}{2}\] since (1+i)(1-i)=1-i^2=1-(-1)=2
@mukushla thank you :D
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