Question

solve 8 = 2^(x+4)

Answer 1

2^3=2^(x+4)
x+4=3
x=-1

Answer 2

just notice
\[\huge 2^{x+4}=2^3 \\ since \\ \huge 8=2^3\]

Answer 3

we can write 8 as 2^3
when bases are equal we can equate powers
2^3=2^(x+4)
x+4=3
x=-1

Answer 4

\[8 = 2^{x+4}\]
change both sides into same bases first. since \(8 = 2^3\)

\[2^3 = 2^{x+4}\]

now use the principle \(\text{if} \; \; a^b = a^c \; \text{then} \; b = c\)

\[\text{since} \; \; 2^3 = 2^{x+4} \; \; \text{then} \; \; 3 = x+4\]
now we solve for x

\[3 = x+ 4\]
\[3 - 4 = x + 4- 4\]
\[3 - 4 = x\]
\[-1 = x\]

Answer 5

First try to make the bases same both in L.H.S. & R.H.S as\[2^3=2^{x+4}\]Now if the bases are equal then the powers are also equal so\[3=x+4\]\[-1=x\]

Answer 6

thanks! im stuck on this problem too...