A charge of 1.5μC is located at (0,0) and a charge of 2.1μC is located at at (4m,0). What is the potential at (4m,3m)?

Question

anonymous · Answer

apply dipole formula

anonymous · Answer

Would that be (1/(4(pi)e0)) * Q/r?

anonymous · Answer

consider it as a dipole find distance of point find potential

anonymous · Answer

What I don't get is how to find potential.

anonymous · Answer

http://www.phys.uri.edu/~gerhard/PHY204/tsl100.pdf

anonymous · Answer

Apply superposition. potential created by charge 1.5uC and potential created by charge 2.1 uC in point (4,3)

Formula for dipole requires:
1.-Center of line between charges is in the origin
2.-Charges are equal but opposite signs
3.-Formula valid for a distance much greater than the distance between charges
None of these conditions is accomplished to apply the formula, then superposition of potentials

anonymous · Answer

$$V=1/4\pi \epsilon_0[Q_1/r_1+Q_2/r_2]$$

anonymous · Answer

You know how to calculate r1 and r2?