The vertices of triangle ABC on a coordinate grid are A(-1, -1), B(-5, -5), and C(-1, -5). The vertices of triangle AQR are A(-1, -1), Q(-3, -3), and R(-1, -3). Which proportion can be used as a step in proving that triangle ABC is similar to triangle AQR? http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0309_19/image0024e24856f.gif I'm pretty sure the answer is D bc that is the only one that has congruent sides.
@wasiqss
im here :D
yay :) Yeah, I think the answer is D?
well i cant see the image properly :/
Which assessment is this in flvs?
Idk :/ I'm just helping someone.
Can you ask them? I'm in flvs as well so I can look it up
@J.L I could I suppose
beccz still cant see :(
urg okay hold on
okay
Okay what are the choices?
You have to use the distance formula in this question. You find the distance between corresponding vertices
a. AB/QB = 2 √8/8 b. BC/AQ = 4/4√8 c. BC/QR = 4/4 d. AB/AQ = 2√8/√8
c. BC/QR = 4/4
thank you
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