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Mathematics 7 Online
OpenStudy (anonymous):

M'(t)=90t-3t^2 new cases every day. If there were 30 cases reported on the first day, how many new cases were reported on the 7th day?

OpenStudy (anonymous):

M'(t) is the derivative of the number of cases reported?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

OK, great! So, to find M(t) we hav eto integrate M'(t) \[M(t)=\int\limits_{}^{}90t-3t^2 dt\] Do you know how to integrate that?

OpenStudy (anonymous):

thats where Im having my trouble is integrating this problem

OpenStudy (anonymous):

M(t)=45t^2-t^3 +constant To find the constant we have to use this: M(1)=30 (" If there were 30 cases reported on the first day") Can you continue now?

OpenStudy (anonymous):

what variable do i put 30 in

OpenStudy (anonymous):

You have to plug 30 instead of M(t) and 1 instead of t.

OpenStudy (anonymous):

so you plug 30 to find C

OpenStudy (anonymous):

\[30=45*(1)^2-1+C\] Solve for C.

OpenStudy (anonymous):

did you get -14 for C @rafabc02

OpenStudy (anonymous):

Perfect! Well done!

OpenStudy (anonymous):

how many new cases were reported on the 7th day?

OpenStudy (anonymous):

so then do you plug -14 into 45t^2-t^3+C

OpenStudy (anonymous):

C=-14 So: \[M(t)=45t^2-t^3 -14\]

OpenStudy (anonymous):

so you put 7 into t?

OpenStudy (anonymous):

That's it! What do you get?

OpenStudy (anonymous):

1848

OpenStudy (anonymous):

You got it! Congratulations! Any doubt about any step? (Thanks for "best response"!) :)

OpenStudy (anonymous):

nope I think I am ok! Thanks!

OpenStudy (anonymous):

Thanks to you! ;)

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