3a-2(5a+1)+11=4(5-3a)-1

Question

waheguru · Answer

$$3a-2(5a+1)+11=4(5-3a)-1 $$

anonymous · Answer

Start by distribution$$3a-2(5a)+2(1)+11=4(5)-4(3a)-1$$

anonymous · Answer

the third term was supposed to be negative

waheguru · Answer

I have a question about one step 

$$3a-10-2+11=20-12a-1$$
$$3a-1=19-12a $$


If I bring the -12 over will it be positive or nrgative

waheguru · Answer

For the second setp

waheguru · Answer

3a−1=19−12a 

it should be 

3a+12a-1=19 right?

anonymous · Answer

You left out the "a" in 10a in your post up there^

waheguru · Answer

Sry, but my question is will the 12 be postive or negative if i bring it over

Do you guys understant my quesiton
>

anonymous · Answer

Yes you are right..

anonymous · Answer

It will be positive. Technically what you are doing is adding +12 to both sides. This causes  the -12 on the right side to disappear, and +12 to appear on the left

waheguru · Answer

Oops, the problem was the fact I for to add the a in 10 a 

Yea, I was right thanks

anonymous · Answer

It will be positive..

waheguru · Answer

Thanks Guys

hero · Answer

$3a-2(5a+1)+11=4(5-3a)-1 \ 3a - 10a - 2 + 11= 20 - 12a - 1 \ 3a - 10a + 12a = 20 + 2 - 1 - 11 \ (3 - 10 + 12)a = 22 - 12 \ (15 - 10)a = 10 \ 5a = 10 \ a = \frac{10}{5} \ a = 2 $