use substitution to evaluate the limit limit [(1/h)/( ln (1+1/h))] as h goes to infinity
\[\lim_{h \rightarrow \infty} \frac{\frac{1}{h}}{1 + \frac{1}{h}}\]
what
Just formatting the question to make sure it's the one you're asking
its 1/h / ln1+ 1/h you missed the ln (natural log)
L'Hopital
havent learned lhosp..
\[\lim_{h \rightarrow \infty} \frac{\frac{1}{h}}{\ln(1 + \frac{1}{h})}\]right?
\[\lim_{h \rightarrow \infty} \frac{\frac{1}{h}}{\ln(1 + \frac{1}{h})}\]let \(t=\frac1h\) then as \(h\to\infty\) we have that \(t\to0\) so we get\[\lim_{h \rightarrow \infty} \frac{\frac{1}{h}}{\ln(1 + \frac{1}{h})}=\lim_{t\to0}\frac t{\ln(1+t)}\]hm... how to do this without l'hospital...
thats my problem lol
wasnt sure if to problem the h from the 1/h down..
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