\[\lim_{h \rightarrow \infty} \frac{\frac{1}{h}}{\ln(1 + \frac{1}{h})}\]let \(t=\frac1h\)
then as \(h\to\infty\) we have that \(t\to0\) so we get\[\lim_{h \rightarrow \infty} \frac{\frac{1}{h}}{\ln(1 + \frac{1}{h})}=\lim_{t\to0}\frac t{\ln(1+t)}\]hm... how to do this without l'hospital...
OpenStudy (anonymous):
thats my problem lol
OpenStudy (anonymous):
wasnt sure if to problem the h from the 1/h down..
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