PQ and RS are two lines that intersect at point T. Which fact is used to prove that angle PTS is always equal to angle RTQ? The sum of the measures of angles RTQ and QTS is equal to the sum of the measures of angles QTS and PTS. Angle RTQ and angle QTS are complementary angles. The sum of the measures of angles RTQ and PTS is equal to the sum of the measures of angles RTP and QTS. Angle RTQ and angle PTS are supplementary angles.
Is it the first one?
@MrMoose
yes it is
you know that RTQ + QTS = QTS + PTS
Yea I knew that but I wasn't completely sure
you can subtract QTS from each side to get: RTQ = PTS
Can you help me with this one too? Look at the figure shown below. Which step should be used to prove that point P is equidistant from points R and Q? If any one side and any one common angle are equal in triangles PQR and PRS, then their corresponding sides are also equal. If two sides and one included angle are equal in triangles PQS and PRS, then their third sides are equal. In triangles PQR and PQS, if one side and one angle are equal, then their corresponding sides and angles are also equal. In triangles PRS and PQS, all three angles are equal.
I know the two triangles are congruent by SAS
So is it the second one?
yes
Thank you so much!
you are welcome
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