Question

f(x)=x^2-4 is this a quadratic function?

Answer 1

yes because its x raised to 2nd

Answer 2

Vertex: (-1,4)
y-int: (0,11)
x-int: none

Answer 3

can some explain to me how they know this. im new to this

Answer 4

http://www.algebra.com/cgi-bin/plot-formula.mpl?expression=graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C7%28x%2B1%29%5E2%2B4%29&x=0003

Answer 5

go to that website it will explain u

Answer 6

anytime x is raised to the 2nd power it is quadratic

Answer 7

and only the second power

Answer 8

so x and x^3 are not quadratic

Answer 9

oh okay thanks

Answer 10

ur welcome

Answer 11

Well, that's not entirely true. An equation is quadratic if it's a polynomial equation with the highest degree of 2.

Answer 12

If that doesn't make sense, I'll explain.

Answer 13

explain

Answer 14

Well, the full definition is this: An equation is quadratic if it's a univariate polynomial equation with the highest degree of 2.

Univariate means that each term only has one variable...ie 2x, 38z^3, 39y^2, etc.

The degree of an expression containing only univariate terms (or constants) is equal to the power of the term with the *highest* power. Here are some examples:

4x^2 + 5 + 6x^3 -> degree = 3
4x + 5 -> degree = 1
2x^2 + 7x + 5-> degree = 2
8x^6 + 7x4 + 3x^9 + 5-> degree = 9

So basically, if the degree of an expression is 2 it's a quadratic expression. Therefore, if it's an equation that can be reduced to the form below, it's a quadratic equation\[y=ax^2+bx+c\]Where a, b and c are constants.

Answer 15

so basically for f(x)=x^2-4 the highest point would be degree=2?