Question

Given the following perfect square trinomial, fill in the missing term. (Do not type the variable in the blank.)

4x2 + ___x + 49

Answer 1

is this 14?

Answer 2

7

Answer 3

its 14

Answer 4

the polynominal is (2x+7)^2

Answer 5

oops its 28

Answer 6

wait i thought it's be 14 because half is 7 & 7 squared is 49?

Answer 7

oldnt the answer be 14?

Answer 8

wouldnt *

Answer 9

alright all this switching is causingme problems

Answer 10

im prettty sure its 14 haha

Answer 11

\[(a+b)^2=a^2+2ab+b^2\]

if a=2x

\[a^2=4x^2\]


if b = 7

\[b^2=49\]

so these are your a and b's

\[a^2+2ab+b^2=4x^2+2(2x)(7)+49\]
\[4x^2+28x+49\]

Answer 12

so its 28?

Answer 13

it's not 14..you need to divide everything by 4 before you do completing the square

Answer 14

this is so confusing.

Answer 15

i know right

Answer 16

without the 4, it'd be 14

Answer 17

well it doesn't help when someone keeps chiming in o wait this answer this answer.... So i had to start over from scratch

Answer 18

haha yeah

Answer 19

here's a helpful hint

the general equation is \(ax^2 + bx + c\)

\[(\frac{b}{2})^2 = c\]
since we're looking for b we do formula transformation
\[\frac b2 = \sqrt c\]
\[b = 2\sqrt c\]
now our c would be 49/4 because we divided by 4 in the start
\[b = 2 \sqrt{49/4}\]
\[b = 2(7)/2)\]
\[b = 7\]
could it be @Outkast3r09 made a mistake or did i...