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Mathematics 8 Online
OpenStudy (anonymous):

Find the missing part

OpenStudy (anonymous):

the question is missing

OpenStudy (anonymous):

OpenStudy (anonymous):

theres a pic hope that helpes

OpenStudy (anonymous):

apply pythagorean theorem here. . . x^2=base^2+altitude^2

OpenStudy (anonymous):

to find x you have to use the Pythagorean theorem

OpenStudy (anonymous):

Use Pythagorean theorem: \[Perperndicular^2 + Base^2 = Hypotenuse^2\] \[H^2 = 8^2 + 10^2\] \[H = \sqrt{100 + 64}\] Find H from here..

OpenStudy (anonymous):

but wait i got 32/\[\sqrt{2}\]. mind giving me the answer then showin me ur process

OpenStudy (anonymous):

\[\sqrt{164}\]

OpenStudy (anonymous):

What is \(\sqrt{164}\) ??

OpenStudy (anonymous):

then you simplify

OpenStudy (anonymous):

12.80624847

OpenStudy (anonymous):

\(= 2 \times \sqrt{41}\)..

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

12.806 is correct..

OpenStudy (anonymous):

could u put that in radical for for me

OpenStudy (jiteshmeghwal9):

(8)^2+(10)^2=(x)^2 64+100=x^2 164=x^2

OpenStudy (jiteshmeghwal9):

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OpenStudy (jiteshmeghwal9):

|dw:1342671474021:dw|

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