Write an equation of the line that passes through (8, 3) and (4, 3).

Question

anonymous · Answer

Equation of the required line is given by:

$$\large \frac{y - y_1}{y _ 2 - y_1} =  \frac{x - x_1}{x _ 2 - x_1}$$

anonymous · Answer

Plug in the values:

$x_1 = 8$

$y_1 = 3$

$x_2 = 4$

$y_2 = 3$

anonymous · Answer

Or you can multiply both the sides by $y_2 - y_1$

$$\large y - y_1=  (\frac{x - x_1}{x _ 2 - x_1}) \times (y_2 - y_1)$$

anonymous · Answer

I can't get past finding the slope.

anonymous · Answer

I have a misunderstanding there.

anonymous · Answer

So:

$$y - 3 = \frac{x - 8}{4-8} \times (3-3)$$

$y - 3 = 0$

$y = 3$

anonymous · Answer

Or you can find slope first..

I think you got slope as 0..

So use:

$$\large y-y_1 = m(x - x_1)$$

Here m is slope that is 0.

so,

$y - y_1 = 0(x - x_1)$

$y - y_1 = 0$

$y_1$ is 3 here:

$$y-3 = 0$$

$y=3$