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Mathematics 17 Online
OpenStudy (anonymous):

Given the triangle and equation below, what is the value of x? tan∠A - csc∠C = 3x

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@lgbasallote

OpenStudy (lgbasallote):

do you have an answer?

OpenStudy (anonymous):

no what do i do?

OpenStudy (lgbasallote):

find tan A first

OpenStudy (anonymous):

is A the letter on the triangle?

OpenStudy (lgbasallote):

yup

OpenStudy (anonymous):

ok A is 5

OpenStudy (lgbasallote):

@waterineyes can you help? im getting confused lol

OpenStudy (anonymous):

\[\tan(A) = \frac{7}{5}\] Now find the hypotenuse: Using Pythagoras Theorem: \[H = \sqrt{7^2 + 5^2} = \sqrt{74}\] So, \[cosec(C) = \frac{Hypotenuse}{Perpendicular} = \frac{\sqrt{74}}{5}\] According to the question: \[\tan(A) - cosec(C) = 3x\] \[\frac{7}{5} - \frac{\sqrt{74}}{5} = 3x \implies \frac{7 - \sqrt{74}}{5} = 3x\] \[x = \frac{7 - \sqrt{74}}{15}\]

OpenStudy (anonymous):

From the figure:\[\text{Tan}\left[\text{ArcTan}\left[\frac{7}{5}\right]\right]-\text{Csc}\left[\text{ArcCot}\left[\frac{7}{5}\right]\right]=3x \]\[\frac{7}{5}-\frac{\sqrt{74}}{5}=3 x \]\[x=\frac{1}{15} \left(7-\sqrt{74}\right) \]

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