Given the triangle and equation below, what is the value of x?
tan∠A - csc∠C = 3x
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
@lgbasallote
OpenStudy (lgbasallote):
do you have an answer?
OpenStudy (anonymous):
no what do i do?
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OpenStudy (lgbasallote):
find tan A first
OpenStudy (anonymous):
is A the letter on the triangle?
OpenStudy (lgbasallote):
yup
OpenStudy (anonymous):
ok A is 5
OpenStudy (lgbasallote):
@waterineyes can you help? im getting confused lol
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OpenStudy (anonymous):
\[\tan(A) = \frac{7}{5}\]
Now find the hypotenuse:
Using Pythagoras Theorem:
\[H = \sqrt{7^2 + 5^2} = \sqrt{74}\]
So,
\[cosec(C) = \frac{Hypotenuse}{Perpendicular} = \frac{\sqrt{74}}{5}\]
According to the question:
\[\tan(A) - cosec(C) = 3x\]
\[\frac{7}{5} - \frac{\sqrt{74}}{5} = 3x \implies \frac{7 - \sqrt{74}}{5} = 3x\]
\[x = \frac{7 - \sqrt{74}}{15}\]
OpenStudy (anonymous):
From the figure:\[\text{Tan}\left[\text{ArcTan}\left[\frac{7}{5}\right]\right]-\text{Csc}\left[\text{ArcCot}\left[\frac{7}{5}\right]\right]=3x \]\[\frac{7}{5}-\frac{\sqrt{74}}{5}=3 x \]\[x=\frac{1}{15} \left(7-\sqrt{74}\right) \]