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Mathematics 14 Online
OpenStudy (anonymous):

See next comment: Proof of the uniquness of the wave equations

OpenStudy (anonymous):

Prove the uniquness (of solution) of the wave equation. \[u_t=u_{xx}\]\[u_x(0,t)=A(t)\]\[u(\pi,t)=B(t)\]\[u(x,0)=f(x)\]\[u_t(x,0)=g(x)\] Let\[v_t=v_{xx}\]With the same conditions as u_t=u_xx Let\[w(x,t)=u(x,t)-v(x,t)\]Satisfy w_t=w_xx So that the conditions of w(x,t) all equal zero. Let\[E(t)=\frac{1}{2} \int\limits w_x^2(x,t)+w_t^2(x,t)dx,\ge 0\] \[E(0)=\frac{1}{2} \int\limits w_x^2(x,0)+w_t^2(x,t)dx=0\]because both terms in integrad are conditions of w that = 0 \[E'(t)=\int\limits w_xw_{xt}+w_tw_{\tt}dx\] \[E'(t)=\int\limits_{0}^{\pi} (w_xw_t)_xdx\] \[E'(t)=(w_xw_t)|_0^\pi=(w_x(\pi,t)w_t(\pi,t)-w_x(0,t)w_t(0,t))=0\]Because those are conditions that = 0 I can't remember the rest of proof?

OpenStudy (anonymous):

in the first equation should be u_tt=u_xx and what is the v(x,t) ? I know you suppose that w(0,t)=w(pi,t)=0 means zero boundary condition. also E(t) is an Energy and zero at t=0. Could you explain all above,then I can give you a solution.

OpenStudy (anonymous):

I'm not really sure how to explain it. It's supposed to be a proof showing that every wave equation has one and only one unique solution. E(t) is just a name for an "arbitrary" equation used in the proof. I didn't copy down the last bit that my prof wrote down >.>

OpenStudy (anonymous):

ok follow me at least I write them in a right way so you can compare which one has mistake.

OpenStudy (anonymous):

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