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OpenStudy (anonymous):
Could someone please help me with sqrt(3) tan2x=0
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OpenStudy (lgbasallote):
what do you want to do with it?
OpenStudy (anonymous):
solve for x
OpenStudy (lgbasallote):
\[\sqrt 3 \tan (2x) = 0\]
first step divide both sides by \(\sqrt{3}\) what do you get?
OpenStudy (y2o2):
x = 0 or x = 180
OpenStudy (anonymous):
so tan2x=-1/sqrt(3)
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OpenStudy (lgbasallote):
nope. \[\tan (2x) =\frac {0}{\sqrt3}\]
now simplify this
OpenStudy (anonymous):
oh dear! sorry i didnt realise! The question is sqrt(3) tan2x+1=0
OpenStudy (anonymous):
sorry!
OpenStudy (lgbasallote):
haha..then you're right \[\tan(2x) =-\frac{1}{\sqrt 3}\]
OpenStudy (lgbasallote):
now second step. take the arctangent of both sides
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OpenStudy (anonymous):
ok so pi/6?
OpenStudy (lgbasallote):
remember that negative sign...and it's not yet over
OpenStudy (anonymous):
how does the negative affect it?
OpenStudy (lgbasallote):
well it doesnt affect that much
OpenStudy (anonymous):
how do you mean?
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OpenStudy (lgbasallote):
|dw:1342705038280:dw|
OpenStudy (anonymous):
oh ok so when you say take the arctangent, where do you go from there?
OpenStudy (lgbasallote):
so \[2x = -\frac{\pi}{6}\]
now you divide both sides by 2
OpenStudy (anonymous):
ok so x= =pi/12
OpenStudy (anonymous):
-pi/12
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