Question

Use the inverse properties of logarithms to simplify the expression.

e^(1n3)

Answer 1

hint \[\huge e^{\ln x} = x\]

Answer 2

What? I don't understand

Answer 3

which part?

Answer 4

that's actually a property

Answer 5

do you want me to prove it?

Answer 6

It's not l that's a one

Answer 7

wait what?

Answer 8

e^( one times n times three)

Answer 9

\[\huge e^{1n^3}?\]

Answer 10

yes

Answer 11

Except they're all multiplied, 3 is not an exponent

Answer 12

1*n*3

Answer 13

wait 1 times n times 3? \[\huge e^{1n3}\]

Answer 14

yes

Answer 15

well this doesnt make sense to me...let me think a bit

Answer 16

You think you know it apoorvk? If not, I'll just guess.

Answer 17

Are you really typing a reply? i'm about to guess

Answer 18

Actually,

\[\large lnx = \log_ex\]

lnx is just a way of denoting logx to the base e.

Now, there's a very basic property of these logs, that says:

\[\Large a^{\log_bc}=c^{\log_ba}\]

So, in case of \(lnx\), which is \(log_ex\):

\[\Large e^{lnx} = e^{\log_ex} = x^{\log_ee} = {x}\]


Do you now understand what we're doing right here?

Answer 19

it's 1n3 not ln3

Answer 20

@iwanttogohome - is it really '1' times 'n' times '3', or is it a typo and you actually meant 'ln3'??