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Chemistry 11 Online
OpenStudy (anonymous):

HELP!! Radioactive decay problems

OpenStudy (anonymous):

OpenStudy (anonymous):

It is artificial transmutation process. mass of Uranium = Mass of He + Mass of x mass of x = 234-4 mass of x=230 Atomic no.(nuclear charge of Uranium) = Atomic No. of He + Atomic No. of x So , atomic no. of x = 92-2 = 90 So x has atomic no. 90 and atomic mass 230u. so, we can find that x is Thorium.

OpenStudy (anonymous):

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