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Mathematics 13 Online
OpenStudy (anonymous):

The picture shows a barn door. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0400_Subtest_02_08/image0104e271d59.jpg What is the distance BC between the two horizontal parallel bars? 4/cos 45 4 sin 45° 4/tan 45 4 tan 45°

OpenStudy (anonymous):

I think the answer is B? but I just don't know

OpenStudy (anonymous):

it isn't sin because you're trying to find the opposite and you have the adjacent so you're going to use tan

Parth (parthkohli):

\( \color{Black}{\Rightarrow \tan 45 = \Large{BC \over 4} }\)

OpenStudy (anonymous):

I believe it is D tan 45=x/4 4(tan 45)=x

Parth (parthkohli):

Gotta multiply 4 to both sides.

Parth (parthkohli):

If you have to find the hypotenuse, then you may use \(\cos\).

OpenStudy (anonymous):

@rebeccaskell94 did you understand?

Parth (parthkohli):

You just gotta keep it to a ratio where you have a side that is known, and then there's a side that you have to find.

OpenStudy (anonymous):

Ah! Comprende thank you both. If I medal J.L, can J.L medal Parth? I want you both to get a medal. :)

Parth (parthkohli):

|dw:1342717349802:dw|

Parth (parthkohli):

If you have to find the opposite, then you will use a ratio where we have opposite and adjacent. \(\tan\) will be a choice right here.

Parth (parthkohli):

My mistake. It'd be a ratio where we have the hypotenuse and opposite. Therefore, \(\sin\).

Parth (parthkohli):

@rebeccaskell94 This will help you attempt all the questions. Remember: Ratio where you got the known and the wanted side.

Parth (parthkohli):

Rap it, eat it, digest it, assimilate it, excrete the waste and the moment you completed, you are a legend at Trigonometry.

OpenStudy (anonymous):

Oh wait, sorry. Is the answer here C?

OpenStudy (anonymous):

It's D

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